00:01
Hi, in this question, we're giving that two automobiles, a and b, approaching jada, let's say a is here approaching at 65 mph, and b is approaching the position at 40 mph, and this is point p, point q, a t -cultzure at point p and q respectively.
00:31
A, but told that it takes 40 seconds after b, it takes 40 seconds for a to get to q after b was there.
00:41
So since b was there at t equal to zero, it takes 40 seconds for a to travel from p to kill.
00:47
So time for a equal to 40 seconds.
00:52
This stands for a displacement for a, equal to 3 ,200 feet.
01:00
The acceleration don't want to find.
01:02
Unknown.
01:04
Incha velocity of a, u equals 65.
01:08
Mph and 65 mph is equal to 29 .06 meters per second and 2 ,200 feet is equal to 975.
01:31
0 .36 meters.
01:35
So the formal i'm going to use is s is equal to u t plus 1 over 2, 80 squared.
01:41
S is the distance which is here as a used in job velocity.
01:47
T's the time is the acceleration.
01:51
So we can substitute 975 .36 is equal to 209 .06 40 equals 1 over 2, a 40 squared.
02:09
And the acceleration of a is equal to minus 0 .2 .2 200 per second square...