Two bars are homogeneous and have a mass of rhokgunit length...

Two bars are homogeneous and have a mass of $\rho$kg/unit length. Determine the angular velocity of the bars when they become colinear if the system is released from rest in the position shown: Use: $l = 1.89 m$ $g = 9.81 m/s^2$ What is the angular velocity of bar AB to 2 decimal places? Question 6 What is the angular velocity of bar BC to 2 decimal places? Use: $l = 1.97 m$ $g = 9.81 m/s^2$

Transcript

00:01 Let us first draw the displacement diagram of the road.

00:04 So let us draw a rough sketch of initial and final position.

00:10 This is just a rough sketch.

00:14 This is just a rough sketch.

00:23 This is just a rough sketch.

00:28 So this is mass m2 and this is this point.

00:36 And here we have this point is c.

00:40 And this is a 2b distance this point is o and this angle is 90 degree let this is is h and this is a1 this is m1 and this point is b this is nothing but a rod this is the rod this is rod this is rod whose mass is m1 similarly this is initial initial position here angle is 90 degree now in final position we have this arrangement.

01:20 Now this has angle 60 degree.

01:26 And this is mass m2.

01:33 This is mass m2.

01:35 So this is m2, this angle is 60 degree.

01:42 And this is a2.

01:44 And this point is point is point c.

01:51 This angle is 60 degree this point is a 2 and this is o and this is h and this is 2b this is point b and mass is mm 1 and this is 2b so so let us find this is final position final now let us find the initial length of link ac so length of link ac is a 1c is equal to square root of oa1 square root of oa1 square plus o c square so it will be equal to square root of b square plus 2b square so from here we get a1c is equal to root under 5 b so this is initial initial length initial length initial length now we will calculate the final length we will calculate the final length so we will write a 2c this will be equals to square root of square root of o a2 square plus oc square minus 2 o a 2 o a 2 o c c c plus 60 degree so let us put the very values here, a to c will be equal to square root of b squared plus 2b square plus 2b square minus 2b 2b plus 60.

03:44 For further solving upon further solving we will get a to c is equal to root under 3b.

03:53 This is final line...

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