00:01
For part a, we'd like to determine the acceleration of each box and the tension in the string.
00:07
So let's draw a free body diagram for mass 1.
00:09
Here is mass 1.
00:11
We have our weight force downwards, our normal force upwards, and our tension force to the right.
00:17
We can let our acceleration.
00:19
Our tension is equal to mass times acceleration.
00:23
Now for m2, we have our weight force, m2g, our applied force, our tension force, and our normal force.
00:35
So from 2, we have f minus tension is equal to m2 times a.
00:41
So if we add up our equations, our two equations together, we have force is equal to m1 plus m2 times a, or acceleration is equal to force divided by m1 plus m2.
00:56
So if we plug in our values, we have 76 divided by 30 plus 14, and so our acceleration is 1 .73 meters per second squared.
01:08
So now we can use this expression in our very first equation written here.
01:14
And we're able to solve for our tension and our acceleration.
01:19
So our acceleration for m1 is equal to 1 .73 meters per second squared.
01:25
Our acceleration for m2 is also 1 .73 meters per second squared...