00:01
Hello, here we are pushing a card which has a mass of 2 kilograms and a speed of negative 2 meters per second.
00:17
And at the same time the lab partner is pushing a second card, which has a mass of 3 kilograms, in positive direction with a speed of 2 meters per second.
00:32
So the cards collide, but not still.
00:37
Together and the sensor on the third on the second card indicates that is experiencing the impulse of negative six kilograms meter per second first we have to draw the diagram of the two cards just before the collision so here let's direct x -axis to the right and we are pushing card one to the right and card 2 is being pushed by the lab partner to the left.
01:27
So that's answer to question a.
01:30
Now let's answer question b.
01:32
And in b we have to calculate the impulse acted on the first card.
01:47
So here let's show the impulse acted on the first card.
01:51
So that is sorry on a second card so this impulse p2 is negative 6 therefore is directed to the left so this is p2 and therefore p1 is in the opposite direction so then p1 is directed to the opposite direction and delta p1 vector equals to negative delta p2 vector therefore delta p1 equals to 6 kilograms meter per second and now in question c we have to calculate velocity of each card after the collision so let's start with a card number 1 so it's delta p1 equals to m v 1 final minus m v1 initial and therefore if we projected on the x -axis delta p1 equals to m times sorry that equals to m b1 final minus negative m b1 initial therefore, from here mv1 final equals to delta p1 minus m1 v1 initial.
03:54
So therefore the final v1 final equals to delta p1 over m minus v1 initial...