Two charges (-2.0 nC and +4.0 nC) are fixed on the x axis, as shown in the diagram. Determine the electric potential at points A, B, C and D.
Added by Chad S.
Close
Step 1
It is given by: V = kQ/r where: - V is the electric potential, - k is Coulomb's constant (approximately 9.0 x 10^9 N m^2/C^2), - Q is the charge, and - r is the distance from the charge. Now, let's calculate the electric potential at each point. Point A: This Show more…
Show all steps
Your feedback will help us improve your experience
Suman K and 65 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(II) Two point charges, 3.0$\mu$C and -2.0$\mu$C are placed 4.0 cm apart on the $x$ axis. At what points along the $x$ axis is ($a$) the electric field zero and ($b$) the potential zero?
ELECTRIC POTENTIAL
Electric Potential Due to Point Charges
(II) Two point charges, 3.0$\mu \mathrm{C}$ and $-2.0 \mu \mathrm{C}$ , are placed 5.0 $\mathrm{cm}$ apart on the $x$ axis. At what points along the $x$ axis is $(a)$ the electric field zero and $(b)$ the potential zero? Let $V=0$ at $r=\infty$ .
The two charges in Figure P25.12 are separated by $d=$ 2.00 $\mathrm{cm} .$ Find the electric potential at (a) point $A$ and (b) point $B$ , which is halfway between the charges.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD