Two charges each move perpendicular to a magnetic field...

Two charges each move perpendicular to a magnetic field. Charge X has twice the charge and half the velocity, as compared to charge Y. Which is correct, about the magnitude of the forces acting on these charges? The force on charge X is smaller by 1/4, as compared to Y The force on charge X is smaller by 1/2, as compared to Y The force on charge X is four times larger, as compared to Y The force on charge X is two times larger, as compared to Y The forces have the same magnitude

Transcript

00:01 Hello everyone, so let's start with a question.

00:02 So in a question there is an equal charges, one at rest and the other is having a velocity of 10 to 4 meter per second are released in a uniform magnetic field which charge has the largest force exerted on it by the magnetic field.

00:16 So there is two charges that is charge charge 1 which is at rest and charge 2 which is moving with the speed of 10 to 4 meter per second in a magnetic field which is released in a uniform magnetic field so which of the charge means which of the charge has the largest force exerted on it by the magnetic field okay so for a moving charge for a moving charge the force on a moving charge particle with velocity in a uniform magnetic field give can be given by the formula of that is f is equal to q v b sine theta okay so this is the formula and he here q is our what charge v is our velocity of a charge and b is a magnetic field okay if i talk about the charge of our charge one so it is at rest so its velocity is zero so for the first charge its force will is zero newton okay and for the second case as you can see for the charge two it is moving with the speed of 10 to 4 meter per second in a magnetic field so we have to find the maximum means we have to find the maximum force okay so when the force become maximum okay so as you can see here is angle and this theta is angle between between velocity and magnetic field okay so suppose for the charge to if i if i write that is if sine 90 degree is equal to one so i can write that is q v b and if sine zero degree is 0 then f2 will be 0 so we have to find the maximum so for the maximum our for the maximum force their angle between means between the angle velocity and magnetic field it should be 90 degree then only we will get then only we get our maximum force so here if i write to get the maximum force angle between velocity and magnetic field it should be perpendicular so from the for the from the given charge our f2 means our second charge is having a maximum force so from the given option our option is is that is option c that is the charge that is moving its velocity sorry not option c option b the charge that is moving if its velocity is perpendicular to the magnetic field the reason when it release...

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