Two charges of 25 pC and -41 pC are inside a cube with sides that are of 0. 3 m length. Determine the net electric flux ( in units of N · m²/C) through the surface of the cube. use ?? = 8.8542×10?¹² F·m?¹.
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Given: \(Q_1 = 25 \times 10^{-12} C\) \(Q_2 = -41 \times 10^{-12} C\) Net charge inside the cube: \(Q_{net} = Q_1 + Q_2\) \(Q_{net} = 25 \times 10^{-12} C - 41 \times 10^{-12} C\) \(Q_{net} = -16 \times 10^{-12} C\) ** Show more…
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