00:01
In this problem, we have been given that there are two charges, q1 and q2.
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And these two charges are separated by a distance d.
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And they exert a force of f -newtons onto each other.
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And using kulam's law, that is, f equals k times q1, q2 by r -square, k is just a constant, which has the value 9 -0 meter square per column square.
00:28
Q1 and q2, these are the charges and r here, that's the separation between these two charges.
00:34
So here, the separation in the given case is d.
00:37
So using this column's law, we need to identify the new force that these charges will experience under the given conditions.
00:46
So the first condition, here we are given that q1, that is tripled.
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So when q1 is tripled, it means it's made three times, and we observed that the force is directly proportional to the product of the two charges.
01:01
So as q1 is made three times, the force here will also become three times.
01:07
So the new force that the charges will experience now will be 3f.
01:12
In the next case, we are given that both q1 as well as q2, they are reduced to one -fourth of their value...