Two coils A and B are connected in series across a 240V, 50Hz supply. The resistance of A is 5 ohm and the inductance of B is 0.02H. The power consumed is 3KW and the power factor is 0.75. The impedence of the circuit will be ?
Added by Sotor S.
Step 1
Given that P = 3KW = 3000W, V = 240V and cosθ = 0.75, we can rearrange the formula to find the current I: I = P / (Vcosθ) = 3000 / (240 * 0.75) = 16.67A. Show more…
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