Question

Two coils are wound on the same iron rod so that the flux generated by one passes through the other also. The primary coil has $N_{p}$ loops and, when a current of $2.0 \mathrm{~A}$ flows through it, the flux in it is $2.5 \times 10^{-4} \mathrm{~Wb}$. Determine the mutual inductance of the two coils if the secondary coil has $N_{s}$ loops. $$ \left|\delta_{s}\right|=N_{s}\left|\frac{\Delta \Phi_{M s}}{\Delta t}\right| \text { and }\left|\delta_{s}\right|=M\left|\frac{\Delta i_{p}}{\Delta t}\right| $$ give $\quad M=N_{s}\left|\frac{\Delta \Phi_{M s}}{\Delta i_{p}}\right|=N_{s} \frac{\left(2.5 \times 10^{-4}-0\right) \mathrm{Wb}}{(2.0-0) \mathrm{A}}=\left(1.3 \times 10^{-4} \mathrm{~N}_{s}\right) \mathrm{H}$

          Two coils are wound on the same iron rod so that the flux generated by one passes through the other also. The primary coil has $N_{p}$ loops and, when a current of $2.0 \mathrm{~A}$ flows through it, the flux in it is $2.5 \times 10^{-4} \mathrm{~Wb}$. Determine the mutual inductance of the two coils if the secondary coil has $N_{s}$ loops.
$$
\left|\delta_{s}\right|=N_{s}\left|\frac{\Delta \Phi_{M s}}{\Delta t}\right| \text { and }\left|\delta_{s}\right|=M\left|\frac{\Delta i_{p}}{\Delta t}\right|
$$
give $\quad M=N_{s}\left|\frac{\Delta \Phi_{M s}}{\Delta i_{p}}\right|=N_{s} \frac{\left(2.5 \times 10^{-4}-0\right) \mathrm{Wb}}{(2.0-0) \mathrm{A}}=\left(1.3 \times 10^{-4} \mathrm{~N}_{s}\right) \mathrm{H}$

Added by Veronica F.

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