00:01
Hi, i'm david and i'm here to have you answer your question.
00:04
Now let me bring up your question here.
00:07
In the question we have two cons that will be flipped.
00:12
The first one, it needs the bias cone where we have the probability to get the head equal to 0 .16.
00:19
The second one, the probability can the head will be 0 .7.
00:23
So i use the blue one for the first cone.
00:32
And then the orange one for the second cone here so the outcomes we can have it will be the head and the head or it can be the head and the tail or it can be the tail or it can be the tail and the head or it can be the tail and the tail.
01:03
So that will be the totally four outcomes we can get when you flip the two cons.
01:10
And now this one will have the outcomes there and then x will be equal to the number of the head.
01:22
So number of the head for the first case will be equal to the two.
01:27
For the second case will be equal to 1 1 and this one will equal to the 0 and we want to find the corresponding probability so that outcome to get the head head so it must have the 0 .6 that would be the probability again the first one will be head times the second one will be 0 .7 so if we multiply got the 0 .42 now for the second event, we should get the head for the first one will be 0 .6.
02:02
The second one will be 10, so 1 minus 0 .7 will be 0 .3.
02:08
If we compute it, we get equal to the 0 .18.
02:12
For the third event, we have the tail for the first one, so it will be 1 minus 0 .6, which is 0 .4.
02:20
And get the head for the second one will be 0 .7...