8 in., 10 in., 10 in. A, B, C, D P, 14 kips 1 1/8-in....

Transcript

00:01 So here on this problem we are given with two cylindrical road the part ac is made up of aluminum and the part cd is made up of steel now these two roads are restrained by two rigid support as you can see in this figure and the youngs model is of aluminum we are given as 10 .4 times 10 to the power 6 psi and the youngs model is for steel we are given as 29 times 10 to the power 6 psi and the magnitude of this force p we are given us 34 kips and we have to calculate the reactions at point a b c and d now at point b and c we know it is 34 kips and at point c it is 14 kips but let the reaction at point a b r a and let at point b b r d now we'll be calculating reactions are a and r d now if you use a little condition in x direction we can write that r a plus r b would be equals to p plus 14 so p we have 34 kips and at this point we have 14 kips so from here we'll get r a plus r b as 84 kips and in pounds r a plus r b would be equals to 48 times 10 to the power three pounds now next we know that these two roads are restrained by rigid support so their change in length would be equals to zero so delta l of the road a d would be equals to zero so this would be equal to the change in length of the road ab plus change in length of the road bc plus change in length of the road cd would be equals to zero now the formula to calculate a change in length delta l is given by fl by ae so if you consider this section we have the force acting in the section would be equals to ra so r a times length so length we have 8 inch so 8 inch divide by area so area is pi by 4 d square so here diameter is 1 by 8 inch that would be 9 by 8 inch square times e so e we have this much this is aluminum so we will take this much so 10 .4 times 10 to the power 6 psi plus now length the change in length for the bar bc so here you to consider the cross section here and the force acting at this cross section would be r a minus p and p we have 34 kips but in pounds we get 34 thousand pounds divide by pi by 4 d square so pi by 4 d square is the same that is 9 by 8 inch square times e we have this month so 10 .4 times 10 to the power 6 psi plus the changing length for the bar cd so we have a cross -section here and the force acting at this cross -section would be r a minus this one is p plus 14 so it would be 48 kips so that would be 48 thousand pounds divide by pi by four d square this time d would be this is one five by eight five by eight so d would be 13 by eight squared times e we have to take this much so 29 times times to the power 6 psi and that should be equals to 0 now here we have only one variable that is ra we can calculate ra from here easily so by using our calculator will get the value of ra as 21426 .4 .4 pound and in kips it would be 21 .4 .4 2 kips and now if you put the value of ra in this expression so it should be be actually i did a mistake here it we have taken the reaction at point d to be r d so it should be already here now r a we have calculated as this much so r d should be equals to 48 kips minus this one 21 .42 kips so from here reaction at point d it would be 26 .58 kips so finally we can conclude that the reaction at point a it will be 21 .4 two kips, kilo pound and the reaction at point d it would be 26 .58 kips.

05:38 So this is a final answer...

Question

8 in., 10 in., 10 in. A, B, C, D P, 14 kips 1 1/8-in. diameter 1 5/8-in. diameter

Question

8 in., 10 in., 10 in. A, B, C, D P, 14 kips 1 1/8-in. diameter 1 5/8-in. diameter

Please give Ace some feedback