Two dice and two coins are tossed, find the probability...

Two dice and two coins are tossed, find the probability that numbers greater or equal than three and two heads are obtained. 11% 33% 22% 12.5% Question 2 20 pts A bag contains 12 red, 10 green, 2 yellow, 19 blue, and 9 purple marbles. The marbles are taking with replacement. Compute the probability that the first marble will be red and the second and third marbles will be yellow. 0.02% 0.03% 0.89% 30.77%

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Transcript

00:01 Hello student, given that two dice and two coins are tossed.

00:08 So here we have to find out the probability that the number is greater than or equal to 3 and two heads are obtained.

00:18 Now, suppose two dice are tossed when there are four possible outcomes for each die that the number greater than or equal to 3 that is 3 comma 4 comma 5 comma 6.

00:31 So there are total outcomes is equal to 4.

00:36 So here 4 into 4 there are total 16 possible outcomes.

00:40 Now here we have to find out probability of number greater than or equal to 3.

00:50 So here number greater than or equal to 3.

00:54 So here probability is calculated as 16 divided by 36.

00:59 Now here we have given again two coins are tossed.

01:03 Suppose two coins are tossed then sample space s is equal to hh ht eh and tt.

01:18 So there are number of sample space is equal to 4.

01:23 Now here we have to obtain probability of two head.

01:27 So there is only one event.

01:30 So here probability of two head is equal to 1 by 4.

01:35 Now here we have to multiply this two probability.

01:39 So here probability is equal to 16 divided by 36 into 1 divided by 4 here 4 divided by 36.

01:51 We have 4 divided by 36 is equal to 1 by 9.

01:55 Now we divide it and multiply it by 100 and we get probability is equal to 11%...

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