Question

Two different mixtures of gases are being studied to determine whether one is superior in reducing the variability of the oxide thickness. Sixteen wafers are etched in each gas. The sample standard deviations of oxide thickness are s1 = 1.96 angstroms and s2 = 2.13 angstroms, respectively. Is there any evidence to indicate that either gas is preferable? Use a fixed-level test with α = 0.05. f0.975,15,15 = 0.35, f0.025,15,15 = 2.86.

Name: two different mixtures of gases are being studied to determine whether one is superior in reducing the variability of the oxide thickness sixteen wafers are etched in each gas the sample sta 59875
Uploaded: 2024-01-14T00:45:07-08:00
Duration: 1 min 36 s
Channel: Lien Le
Description: two different mixtures of gases are being studied to determine whether one is superior in reducing the variability of the oxide thickness sixteen wafers are etched in each gas the sample sta 59875

          Two different mixtures of gases are being studied to determine whether one is superior in reducing the
variability of the oxide thickness. Sixteen wafers are etched in each gas. The sample standard deviations of
oxide thickness are s1 = 1.96 angstroms and s2 = 2.13 angstroms, respectively. Is there any evidence to indicate
that either gas is preferable? Use a fixed-level test with α = 0.05. f0.975,15,15 = 0.35, f0.025,15,15 = 2.86.

Added by Tamara F.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Lien Le

01/14/2024

Step 1

- Alternative Hypothesis (H1): The variances of the two gases are not equal (σ1² ≠ σ2²). Show more…

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Two different mixtures of gases are being studied to determine whether one is superior in reducing the variability of the oxide thickness. Sixteen wafers are etched in each gas. The sample standard deviations of oxide thickness are s1 = 1.96 angstroms and s2 = 2.13 angstroms, respectively. Is there any evidence to indicate that either gas is preferable? Use a fixed-level test with α = 0.05. f0.975,15,15 = 0.35, f0.025,15,15 = 2.86.