two electric charges, q1= +20.0 nC and q2= +10 nC are located on the x axis at x=0 m and x= 1.00 m respectively. What is the magnitude of the electric field at the point x= .50 m, y= .50 m?
Added by Remedios W.
Step 1
The electric field due to a point charge is given by the formula E = k*q/r^2, where k is Coulomb's constant (9.0 x 10^9 N*m^2/C^2), q is the charge, and r is the distance from the charge to the point of interest. Show more…
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