00:02
So let's say we have a coordinate plane and here we have two charges and these two charges are having magnitude q and they are positioned at one let's say it is positioned at l0 and another q charge is positioned at minus l0.
00:24
So we need to find out the electric field at any point on the y -axis.
00:29
So let's say this is at y distance from the origin so it's this point will be zero by and here if we find out the electric field, so due to this charge, the electric field will be in this direction.
00:44
And due to this charge, electric field will be in this direction.
00:48
So the magnitude will be same because the charge and the separation is same.
00:51
So let us find out one electric field.
00:54
So that will be k, q by this separation squares.
00:59
So this is l and this is y.
01:01
So separation will be root of l square plus y square by using pythagoras root.
01:06
In this right angled triangle.
01:10
So this square will be l square plus y square.
01:14
So that is the electric field.
01:17
So this will also be e.
01:19
But due to symmetry here, this if we take it as theta, this also will be theta, and this also will be theta.
01:30
To find out the net electric field, let us project the electric fields.
01:34
So if you project this electric field, it be e sine theta in this direction and e cost theta in this direction...