1. Two forces act on a 4.5-kg block resting on a frictionless surface as shown. What will be the horizontal velocity of the block after 25 seconds if the block was initially in equilibrium? 3.7 N 5.9 N 43°
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Given: Force F1 = 3.7 N Force F2 = 5.9 N Mass of the block (m) = 4.5 kg Angle theta = 43 degrees The component of F2 along the x-axis is F2 cos(theta). Therefore, the net force on the block along the x-axis is F1 + F2 cos(theta). Substitute the values: Net force Show more…
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