Two forces are acting on a body one acts east the other at...

Two forces are acting on a body. One acts east, the other at 35° north of east. If the two forces are equal in magnitude of 50 N, find the resultant using the Law of Sines and the Law of Cosines.

Transcript

00:01 In this question we have given an iron washer and it is told that the washer is heated to a 750 degrees celsius and then it is plunge into a bicker which contains 100 m l of water at 20 degrees celsius.

00:14 We have to find the final temperature of the water.

00:18 So first of all i am calculating the mass of this iron so we can say that volume of iron washer is this is calculated from the given diagram so we can say this is.

00:34 Is equal to v is equal to this is pi into this is 20 by 2 square minus this is 6 by 2 square into 10 to the power minus 6 into this is 3 into 10 to the power minus 3 in meter cube this is actually hollow washer so i'm subtracting the radius of the bigger to the radius of the smaller portions so finally we can say this will comes out to be 857 .66 into 10 to the power minus 9 meter cube we have given the density of the iron so we can say that mass of iron washer is that is m i is equal to this is density into volume so we can say this will come out to be now if we put the value of density here this is 7 870 into this is 10 to the power 3 in grams into this is 8 57 point 66 into 10 to the power minus 9 so from here we can say this will comes out to be 6 .75 in grams now let t is the final temperature of water so we can say that from energy conservation that heat lost by iron washer is equal to this is heat gain by water so we can say that this is equal to now heat lost by iron can be calculated this is mass of iron into specific heat of iron into this is temperature difference that is 750 minus t and this is equal to heat again so we can say this is equal to mass of water into this is specific heat of water into this is t minus 20 so now put all the data in this equation so mass of iron we had calculated that is 6 .75 into a specific heat of iron is given to us that is 449 into this is 750 minus t is equal to now mass of iron is this is 100 grams into this is 4 to 0 0 into this is t minus 20 or we can say after solving this we get this is 420 t plus 3 .03 into t is equal to this is 8400 plus 840 plus 2 to 73 .55 from here we get the final temperature t and this will comes out to be this is 10673 .55 upon 423 .03 .03 that is equals to 25 .23 in degrees celsius...

Question

Two forces are acting on a body. One acts east, the other at 35° north of east. If the two forces are equal in magnitude of 50 N, find the resultant using the Law of Sines and the Law of Cosines.

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