00:01
All right, so let's say we have two forces acting at a point.
00:04
One of them points at an angle of 64 degrees.
00:08
That's probably not a very good.
00:09
64 degree angle, huh? so let's say this is 64 degrees, and it has a magnitude of 8 newtons.
00:16
Let's say this is force one.
00:18
You have another force that has a magnitude of 6 newtons that is directed at 54 .1 degrees.
00:28
It has a magnitude of 6, and we'll call it the 6.
00:30
F2 and we want to know what is the x component of the resulting vector so fx is going to be eight newtons times the cosine of 60 or sorry negative eight newtons times the cosine of 64 degrees minus six newtons times the cosine of 54 .1 so let's see what do we get when we do that 54 .1, the cosine of that times six plus cosine of 64 times eight.
01:14
Yes, so we should get negative 7 .025 newtons.
01:20
Part b asks, what are the y components? so a similar approach here, so we're going to be having signs instead of cosines...