Two infinitely long thin lines of charge are arranged...

Two infinitely long, thin lines of charge are arranged parallel to each other and separated by a constant distance of 15.3 cm. The one on the left has charge density -9.34 nC/m while the other is on the right and has charge density 5.12 nC/m. What is the magnitude and direction of the electric field at point P, midway between the two lines? What would be the force (magnitude and direction) on an electron if it was placed at point P?

Transcript

00:01 For the given problem it has been seen that there are two infinite wires these are infinite wires that are kept at a distance of 15 .3 centimeters for one of the wire for the left wire the charge density is minus 9 .34 newton coulum per meter and for the right wire the charge density is 5 .12 newton cullum per meter also from we need to find the electric field at a point p which is at the midway from this wire so if we recall if we recall that for infinite charge for infinite charge the value of electric field is equal to lambda divided upon two pi r epsilon not therefore for the point p for p that is also that the value p is in midway so we can write that the value r will be 1 point sorry 15 .3 divided upon 2 that will also be equal to 7 .65 centimeter that is also in meter we can write it as 0 .0 765 meter here the value of the net force the net force will be written as lambda 1 plus lambda 2 divided upon 2 pi r epsilon not for which we have the value of lambda 1 to be 9 .34 the negative denote the type of the charge so we'll write just 9 .34 plus 5 .12 and it will be multiplied to 10 to the power minus 9 at least is a nanoculum divided upon 2 pi multiplied to 0 .0765 multiplied to 8 .85 multiplied to 10 .m .12 and the value of f net will be equal to 3399 .25.

02:09 Newton per column also the direction the direction is leftward this is because e electric field is away from the positive charge this is for the negative charge case also for the next scenario it has been told that if an electron is placed if electron is sorry electron is placed at point p there therefore in this scenario we can say that the direction of e will now change that will be opposite now the direction of electric field will be now rightward.

03:00 Also the value of f will be equal to the charge of electron multiplied to the f net...

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