00:02
Here we have two perpendicular wires which are in the same plan.
00:14
It is considered the vertical wire as wire 1 and the wire which is horizontal taken as wire as point p and point q are at equal distance from wire 1.
00:46
So we have magnitude of magnetic field at point p and point q due to wire 1 is equal to mu not times current through wire 1 divided by 2 pi into distance of point p and point q from the wire that is r1 now we can put different values here mu not is 4 pi times 10 to the power minus 7 tesla meter per ampere and current through wire 1 is 12 ampere divided by 2 pi distance of point p and point q from wire 1 is 15 centimeter that is 15 times 10 to the power minus 2 meter this gives us the magnitude of magnetic field at point p and point p and point q due to wire 1 equal to 1 .6 times 10 to the power minus 5 tesla.
02:15
Similarly we can write the magnitude of magnetic field at point p and point q due to wire 2 as b2 equal to mu not into i2 divided by 2 r2 again putting the values here mu not is 4 pi times 10 to the power minus 7 tesla meter per ampere into current through second wire is 10 amp divided by 2 pi into distance of point p and point q from second wire is 8 cm that is 8 times 10 to the power minus 2 meter this gives us b2 equal to 2 .5 times 10 to the power minus 5 tesla in part a of this problem we are considering the direction of current in y is from left to rise now we want to find the n magnetic field at point p and point q due to these both wires.
04:04
First we will take the point p.
04:16
At point p we can find the direction of magnetic field produced by wire 1 and wire 2 by using right hand rule.
04:31
So by right hand it is clear.
04:35
That direction of magnetic field at point p due to wire 1 that is b1 is into the page also due to second wire magnetic field is also into the page so we will have the net magnetic field at point p equal to b1 plus b2 as b1 is equal to 1 .6 times 10 to the power minus 5 tesla plus b2 is 2 .5 times 10 to the power minus 5 tesla this gives us net magnetic field at point p equal to 4 .1 times 10 to to the power minus 5 tesla and this is the magnitude of net magnetic field and here direction of net magnetic field is into the page.
06:06
Similarly we can find the magnetic field at point q.
06:23
The wire 1 produces magnetic field at point q that is out of page also the wire 2 produces magnetic field which is out of patch.
06:42
So we have net magnetic field at point q that is also out of the page which will be equal to b1 plus b2 as we have b1 equal to 1 .6 times 10 to the power minus 5 tesla and we have b2 equal to 2 .5 times 10 to the power minus 5 tesla this gives us the net magnetic field at point q equal to 4 .1 times 10 to the power 10 to the power minus 5 tesla and here direction of field is out of the page.
07:28
Now in the second part of this problem we are considering the direction of current in the second wire from right to left and we want to again find an n magnetic field at point p and point q...