Two large metal plates of area 1.0 $\mathrm{m}^{2}$ face each other, 5.0 cm apart, with equal charge magnitudes $|q|$ but opposite signs. The field magnitude $E$ between them (neglect fringing) is 55 $\mathrm{N} / \mathrm{C}$ . Find $|q|$
Added by Matthew L.
Step 1
Given: $E = 55 \, \text{N/C}$ $d = 5 \, \text{cm} = 0.05 \, \text{m}$ Plugging in the values, we get: $\Delta V = 55 \, \text{N/C} \times 0.05 \, \text{m} = 2.75 \, \text{V}$ Show more…
Show all steps
Your feedback will help us improve your experience
Nishant Kumar and 97 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Two large metal plates of area $1.0 \mathrm{~m}^{2}$ face each other, $6.0 \mathrm{~cm}$ apart, with equal charge magnitudes $|q|$ but opposite signs. The field magnitude $E$ between them (neglect fringing) is $72 \mathrm{~N} / \mathrm{C}$. Find $|q|$.
Two large parallel metal plates are $1.5 \mathrm{~cm}$ apart and have charges of equal magnitudes but opposite signs on their facing surfaces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then $+5.0 \mathrm{~V}$, what is the electric field in the region between the plates?
Adi S.
Two large metal parallel plates carry opposite charges of equal magnitude. They are separated by $45.0 \mathrm{mm},$ and the potential difference between them is 360 $\mathrm{V}$ (a) What is the magnitude of the electric field (assumed to be uniform) in the region between the plates? (b) What is the magnitude of the force this field exerts on a particle with charge $+2.40 \mathrm{nC}$ ?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD