00:01
For part a of our question, it says it would like us to find the current in the other wire, given the fact that the current in one of the wires, i1, is 5 amperors.
00:09
The force per unit length between the two wires is 2 times 10 to minus 4 newtons per meter, and the distance that separates the wires is 4 centimeters or 0 .04 meters.
00:17
So to do that, we'll use the equation of force per unit length between two long parallel wires, which says that it's equal to the magnetic permeability of free space, mu not, times the current in wire 1, times the current in wire 2, which is what we're trying to find, divided by 2 times pi times the distance of separation.
00:40
Therefore, we can rearrange this equation to solve for the current in wire 2 in terms of everything else that we know.
00:47
So this is f over l, multiplied by 2 pi times d, divided by mu not times i 1.
01:07
Mu not is 4 pi times 10 to the minus 7.
01:10
So we can plug that in as well as all the other values that we know into this expression, and we find that i2, the current in the second wire, has to be 8 .0, ampiers.
01:19
So we can box this in as our solution for part a.
01:25
Now we can begin part b, where for part b, we are asked, are the currents in the same direction or in the opposite direction? well, the rule goes that for long, parallel wires, current in the same direction, are attractive, and currents in the opposite direction repel...