00:01
Hello student, so in that numerical, so this is your pulley and there are two mass are hanging here.
00:08
One mass is a 6 kilogram so we can write here that is a 6 kilogram and other mass is connected with another mass that is a 10 kilogram.
00:18
Obviously you know that that is a rest condition pulley so the body will be moving in the direction of a higher masses.
00:27
So this is a moving in downward direction and it will be moving in an upward direction.
00:32
That is an acceleration a.
00:34
Now according to some situation that is a free body diagram so that is a tension t in downward direction that is a 10g.
00:43
Here the tension t and downward direction that is a 6g.
00:49
Now we apply one by one.
00:51
So free body diagram according to that diagram that is a 10g.
00:57
Table diagram of a 10g so we mentioned that equation so 10g minus of a t is equivalent to a 10a okay second equation we can write here that is a t minus 6g is equivalent to a 6a now that tension and the tension will be cancelled out so we get a values of a 10g minus of a 6g is equivalent to 10 plus 6 that is a 16a...