00:01
Here we have two objects of masses m and 5m respectively.
00:05
Let us first draw the free -body diagram of the object of mass m.
00:10
So here we have an object of mass m.
00:14
Now there is weight of the object acting downwards, that is mg.
00:21
Here we have the inclination angle as theta.
00:23
So this will be m -g cos theta that is balanced with the normal force acting on the mass, acting on the object, that is n, that is acting upwards.
00:34
Now here we have mg sine theta.
00:39
The block or the object is moving downwards.
00:44
So we have acceleration downwards.
00:47
Since it is moving downwards, we have friction force along this direction.
00:53
So this is the free body diagram of object of mass m.
00:56
Now here the mass is m.
01:00
Here we can write the friction force as friction forces coefficient of friction into the normal force.
01:10
Here mu k into normal force.
01:12
So here normal force we know that it is mg cos theta.
01:18
Mg cos theta.
01:20
So this is the friction force.
01:22
Now we can write the force equation as mg sine theta minus friction force equals ma.
01:30
We can substitute the expression for friction force f here.
01:36
F is mu k m g cos theta.
01:41
This is equals to m .a.
01:43
Now here we can cancel all m terms.
01:47
So here we get g sine theta minus mu kg cos theta equals a.
01:55
So this is the expression for acceleration.
02:00
Let this expression be number.
02:02
As 1.
02:02
So this is the acceleration expression for object of mass m...