00:04
The question here is two objects, one having three times the mass of the other, are dropped from the same height in a vacuum.
00:13
At the end of their fall, their velocities are equal because.
00:17
So options are given here.
00:20
Now, let's understand the question first.
00:23
So there is one ball of mass 3m and another of mass m, and they are in vacuum.
00:30
Now when they are dropped, they both touch the ground at same velocity, that is v1, it will be equal to v2.
00:42
Now, the reason for this is the velocity does not depend upon the mass of the object.
00:51
So, only force depends upon the mass of the object, that is, force is equal to m .a.
00:58
So, force depends upon the mass of the object, but velocity, that is initial, final velocity square minus initial velocity square e square minus u square is equal to 2a s so this is according to the newton's equation so we can see in this equation that there is no mass given so the velocities does not depend upon the mass so the force may vary because there is a change in the mass that is 1 is 3m and another is just m so the force may vary but the velocity and the acceleration will be same.
01:38
So this is the reason why the velocity of the both the balls will be equal.
01:44
So if we look at the options, so option states anything falling in the vacuum has constant velocity.
01:51
So that is not true because if the velocity changes, then there will be a different timing of the landing of the object...