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Hello, we have to solve the following problem.
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Two particles have masses of 2m and 4m and they are moving towards each other along x -axis with the same initial v -initial.
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Particle 2m is traveling to the left.
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Let's catch it and particle 4m is traveling to the right.
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They undergo elastic glancing collision in the way that that the 2 -em particle moves in the negative y direction after the collision.
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So let's sketch it.
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Here we will show the coordinate x's y and x.
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And here let's basically sketch this particle, 2m and 4m.
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And after the collision, the 2m particle is moving in a negative y direction.
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So that's going to be v2 final.
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We have to find the final speed of two particles in terms of the v initial.
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Let's do this.
01:33
So here we have the final v1 final and v2 final.
01:45
So let's do this.
01:48
Here, let's presume that, yeah, let's first down, let's first write down the equation for the conservation momentum.
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For the conservation of the momentum.
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So here, 4m times v initial minus as a vector plus 2m times v initial as a vector equals to that equals to 4m v1 final plus 2m times v2 final.
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So now let's write down its projection on the y -axis.
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Here, 4m times v initial minus, actually let's start with the x -axis.
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So 4m times v initial minus 2m times the initial equals to 4m times v .1 final x because the second particle doesn't have any y component.
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And on the other hand, 2m times v2 final equals to 4m times v2 final x2 final y.
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So now we have these two equations and we also need to write down the conservation of the momentum or conservation of energy because the collision is elastic...