The change in potential energy is given by:
\[
\Delta U = q \cdot V
\]
where \( q = -8.30 \, \text{mC} = -8.30 \times 10^{-3} \, \text{C} \) and \( V = 7.25 \, \text{V} \).
\[
\Delta U = (-8.30 \times 10^{-3} \, \text{C}) \cdot (7.25 \, \text{V}) = -0.060175 \,
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