00:01
Hello, here to point charges of plus q and minus 2q are placed at b and c, and we have to find the expression for the magnitude and direction of the resultant electric field at point a.
00:23
Let's do this.
00:24
First of all, let's show this equilateral triangle, and let's label points as a, b, and c.
00:50
Now let's show the x's y and x and here let's illustrate the direction of the fields created by b and c.
01:19
So b is positive, that's why it will create the field from itself, so that is eb and c is negative, church, that's why it will create the field from itself, so that is eb, and c is negative, church, that's why it will create the force which is directed towards.
01:44
See the result in force can be found the result in field can be found as following so ea equals to the vector sum of eb and ec and let's find the projection of ea on x axis so that equals to eb x plus ec x so that is close to eb x plus let's find, let's show some angle, so this is angle of 60 degree and the same angle is here.
02:23
And as well, so this is angle is 60 degree and that's why this is the same angle of 60 degree.
02:45
Then let's find some additional angle which will help us...