Two point charges $Q_1 = -90.0 \mu C$ and $Q_2 = 30.0 \mu C$ are separated by a distance $d_1 = 10.0 \text{ cm}$, as shown in the image. Calculate the potential $V$ at point A positioned $d_2 = 4.00 \text{ cm}$ to the left of $Q_1$.
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0C charge at point A. The electric potential due to a point charge is given by the equation: V = k * (Q / r) where V is the electric potential, k is the Coulomb's constant (9.0 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the charge. In this Show more…
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