00:01
Hello everyone, in this question we have to find the electric potential at point a.
00:05
So, we use the formula v is equal to kq1 upon r1 plus kq2 upon r2.
00:11
Here r1 and r2 are the distances from point a and a is equidistance from both charges.
00:21
That is r1 is equal to r2 equal to 0 .05 right.
00:30
So, plugging in the value we get v is equal to 9 into 10 raised to power 9 nm square by c square is equal to 2 .40 c 0 .05 m plus 9 into 10 raised to power 9 nm square by c square is equal to minus 7 .00 c upon 0 .05 m right.
01:28
So, here v is equal to 1 .728 into 10 raised to power minus 10 v minus 5 .04 into 10 v.
01:45
So, here v is equal to minus 3 .312 into 10 raised to power 10 v.
01:55
So, now here the electric potential at point a is minus 3 .312 into 10 raised to power 10 v.
02:08
This is the electric potential at point a.
02:12
Now, we find the electric potential at point b.
02:15
So, we use the formula but now first we have to calculate the distance from point b.
02:21
So, r1 is equal to 0 .08 m, r2 is equal to 0 .6 m...