00:01
Hello students, in the given question we have to calculate the magnitude of the charge on a as well as on b.
00:07
So the coulm's constant k, we all know that it is equal to 8 .99, multiply with 10 raised to the power of 9 newton meter square per coulum square.
00:20
The magnitude of the charge on a is q1, whereas on b it is equal to q2.
00:28
Now the magnitude of the charge on a is twice that of the b, so q1 is equal to two times of q2 as per the question.
00:37
And the distance between the two point charges is 23 centimetres, which can also be written as 0 .23 meters.
00:46
The magnitude of the force, each charge exerts on the other is 43 newton's.
00:54
So we know that f is equal to kq1, q2, k, q1, q2 divided by d square.
01:05
So we will put down the values in here and we are going to get f.
01:10
Further, we know here that q1 equals to two times of q2...