Question

Two point charges are lying on the y- axis as in the figure: q1 = -4.10 µC and q2 = +4.10 µC. They are equidistant from the point P, which lies on the x- axis. (a) Find the electric field vector field at P? [Hint: Pay attention if any components cancel, saves your calculation] (b) A small object of charge q0 = 8.10 µC and mass m = 1.15 g is placed at P. When it is released, what is the magnitude of its acceleration?

          Two point charges are lying on the y- axis as in the figure: q1 = -4.10 µC and q2 = +4.10 µC. They are equidistant from the point P, which lies on the x- axis.
(a) Find the electric field vector field at P? [Hint: Pay attention if any components cancel, saves your calculation]
(b) A small object of charge q0 = 8.10 µC and mass m = 1.15 g is placed at P. When it is released, what is the magnitude of its acceleration?
        
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Two point charges are lying on the y- axis as in the figure: q1 = -4.10 µC and q2 = +4.10 µC. They are equidistant from the point P, which lies on the x- axis.
(a) Find the electric field vector field at P? [Hint: Pay attention if any components cancel, saves your calculation]
(b) A small object of charge q0 = 8.10 µC and mass m = 1.15 g is placed at P. When it is released, what is the magnitude of its acceleration?

Added by Jeffrey K.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Transcript

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00:01 All right, so let's say we have a negative charge and a positive charge where q1 is this top one.
00:07 This is negative 4 .1 microculems.
00:10 Q2 is positive 4 .1 microculems.
00:15 They are separated by a distance, and we'll just leave that unspecified.
00:23 And we want to find the field at a point midway between them, where this angle is 30 .9 degrees, and this distance is 0 .7.
00:31 1 meters.
00:33 So the field at this point is actually going to be kind of simple.
00:36 It'll be k times q1 over that distance...
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