Two point charges exert a 5 N force on each other. What will...

Two point charges exert a 5 N force on each other. What will the force become if the distance between them is increased by a factor of 2.1? 7.25 N 22.1 N 0.422 N 2.37 N 10.5 N 1.13 N 1.06 N

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Transcript

00:01 Hello, in the question we have given that a pair of point charges attract each other through a coulomb interaction with a force.

00:10 So, force between the two charges is given that is 5 n.

00:15 Then they are placed at a distance of 2 m apart.

00:20 So if the distance remains same and the charges are increased, so one charge is increased by a factor of 8.

00:28 So let's say we have the coulomb interaction given by f is equals to k q1 q2 divided by the distance between them is r.

00:41 So it is r square.

00:43 So and this is given to be 5 n.

00:46 So now they are saying that one of the charge, so let's say q1 prime is 8 times q1.

00:55 So my new force now due to this charge as they have given that one of the charge becomes 8 times q1.

01:07 So i am calling this new charge as q1 prime and that is nothing but 8 times of q1.

01:15 So my new force, therefore, the force becomes, sorry, force becomes f prime.

01:32 Let us call it as f prime is equals to k q1 prime q2 divided by r square because r is same.

01:42 So this turns out to be k times 8 times q1 q2 divided by r square.

01:55 Now we can take the ratios.

01:57 So f prime is nothing but k, 8 i will take out q1 q2 divided by r square divided by f.

02:10 So divided by f.

02:12 So we are just taking the ratio over here...

Question

Two point charges exert a 5 N force on each other. What will the force become if the distance between them is increased by a factor of 2.1? 7.25 N 22.1 N 0.422 N 2.37 N 10.5 N 1.13 N 1.06 N

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