Two point charges q1 9 c and q2 4 c are separated by a...

Transcript

00:01 Hello bacho so in this question we have two charges we have two charges q1 is equal to 9 microculum and q2 is equal to minus 4 microculum okay so and it is separated through a distance of 10 meters so this is our q1 this is our q2 this is 9 microculum and this is minus 4 macrocule so we have have to basically find a point where electric field due to these two charges is zero okay so this is if we put i am finding the point where it can be if we put a charge let's say a positive charge to this side from this side it will attract but it will repeat so not be a positive charge if we put a negative charge here if a negative charge q small charge you put here from q and at a distance of x then it will it will attract this charge and this will repeal so from this we can say it is not a balance condition so the charges either it will be positive or negative not being between this so for that if we put negative charge here minus q charge here at a distance of x from the q so this will repeal but this will attract and it has large value so i think it will maintain the violence position so exactly this is the so i have to find this is position a this is position b and this is c so i have to find the net force at this can be equal so if c if due to a at c will be equal to if at b at c due to so f is equal to k k k1 q2 upon r squared and k k k u2 upon r2 square this is r1 square so in another slide if we solve i'm solving this k to k get cancelled out okay and q1 into q2 what will the value of not is q1 into q2 this is i'm i write it wrong this is q this will be q2 into q sorry for this silly mistake this is q1 due to this one this is my there is some little bit confusing i'm writing it clearly from for by this charge q1 that will be k q1 and the value of this is minus of q upon there is the distance 10 plus x 10 plus x will be equal to k due to q2 at and q minus at a distance x so this and this get cancelled out k to k get conserved now solve for this one qn upon 10 plus x will be equal to q2 upon x square both sides will be it okay not square y a square not square let's solve it okay so q1 into x will be q2 10 plus q2 x so value of q1 is 9 into x and q2 is minus of what minus of four minus of four into ten plus minus of four x so x is uh x will be what nine x 40 is equal to minus nine x minus 4x that is to minus 13 x so x will be minus of 14 upon in negative direction.

05:07 So this saying that this charge not will be in this direction, but minus charge we will take in this direction...

Question

Two point charges q1 = +9 μC and q2 = -4 μC are separated by a distance L = 10 cm, as shown in Fig. 20.24. Find the point at which the resultant electric field is zero.

Question

Two point charges q1 = +9 μC and q2 = -4 μC are separated by a distance L = 10 cm, as shown in Fig. 20.24. Find the point at which the resultant electric field is zero.

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