Two point charges q1 = +2.60 nC and q2 = -6.60 nC are 0.100 m apart. Point A is midway between them; point B is 0.080 mm from q1 and 0.060 mm from q2. Take the electric potential to be zero at infinity. Find the potential at point A. Express your answer in volts. Find the potential at point B. Express your answer in volts. Find the work done by the electric field on a charge of 2.35 nC that travels from point B to point A. Express your answer in joules to two significant figures.
Added by Gloria S.
Step 1
Step 1: The potential at point A can be found by using the formula for electric potential: \[ V = \frac{k \cdot q}{r} \] where \( k \) is the Coulomb constant, \( q \) is the charge, and \( r \) is the distance from the charge. Show more…
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