Question

Two point charges $q_1 = +$2.40 nC and $q_2 = -$6.50 nC are 0.100 m apart. Point $A$ is midway between them; point $B$ is 0.080 m from $q_1$ and 0.060 m from $q_2$ ($\textbf{Fig. E23.19}$). Take the electric potential to be zero at infinity. Find (a) the potential at point $A$; (b) the potential at point $B$; (c) the work done by the electric field on a charge of 2.50 nC that travels from point $B$ to point $A$.

Name: Two point charges q1 = +2.40 nC and q2 = -6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2 (Fig. E23.19). Take the electric potential to be zero at infinity. Find (a) the potential at point A; (b) the potential at point B; (c) the work done by the electric field on a charge of 2.50 nC that travels from point B to point A.
Uploaded: 2023-03-27T23:27:49-08:00
Duration: 1 min 28 s
Channel: Penny Riley
Description: Two point charges q1 = +2.40 nC and q2 = -6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2 (Fig. E23.19). Take the electric potential to be zero at infinity. Find (a) the potential at point A; (b) the potential at point B; (c) the work done by the electric field on a charge of 2.50 nC that travels from point B to point A.

          Two point charges $q_1 = +$2.40 nC and $q_2 = -$6.50 nC are 0.100 m apart. Point $A$ is midway between them; point $B$ is 0.080 m from $q_1$ and 0.060 m from $q_2$ ($\textbf{Fig. E23.19}$). Take the electric potential to be zero at infinity. Find (a) the potential at point $A$; (b) the potential at point $B$; (c) the work done by the electric field on a charge of 2.50 nC that travels from point $B$ to point $A$.

Added by Ashley T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

03/27/2023

Step 1

Since point A is midway between the two charges, the distance from each charge to point A is half of the distance between the charges, which is 0.100 m / 2 = 0.050 m. The electric potential at a point due to a point charge is given by the formula: $V = Show more…

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Two point charges $q_1 = +$2.40 nC and $q_2 = -$6.50 nC are 0.100 m apart. Point $A$ is midway between them; point $B$ is 0.080 m from $q_1$ and 0.060 m from $q_2$ ($\textbf{Fig. E23.19}$). Take the electric potential to be zero at infinity. Find (a) the potential at point $A$; (b) the potential at point $B$; (c) the work done by the electric field on a charge of 2.50 nC that travels from point $B$ to point $A$.