00:02
Okay, so m1 v1 plus m2 v2 equals to m1 plus m2 equals to m1 plus m2 times big v.
00:19
Where m1 and m2 are masses of the two objects, v1 and v2 are the respective initial velocities, and m1 plus m2 are the combined masses after they've stuck, and v is their velocity.
00:32
So we have to consider the time and flight is the total time, in which the object in flight is moving in air.
00:40
So we'd say that t is equal to 2h divided by g, where h is the maximum height.
00:51
And maximum height is represented, is reached in a projectile.
00:56
So we know that h is equal to mu squared, sine squared, theta over 2g, where theta is the angle of the projection and mute is the initial velocity.
01:17
So in projectile motion, momentum is conserved along the two directions that is on the horizontal x -axis and vertical direction of y.
01:31
So along the x direction, just going to do t, we have m1 v1 cosine cosine, plus, m2 v2 that multiplies the negative cosine theta which equals to m1 plus v1 m2 times v sometimes i mouth them are writing don't match as the velocity is the same we can rearrange the equations to just solve for m so then we have m1 minus m2 times v cosine theta, which equals to m1 plus m2, then multiplies v.
02:46
And then we can rearrange again to get v is equal to m1 minus m2 cosine along the x direction...