Question

2 Two pulleys of diameters d1 and d2 and at distance x apart are connected by means of an crossed belt drive. The length of the belt is (Note that r=d/2) (1 Point) $\frac{\pi}{2}(d1 + d2) + 2x + \frac{(d1+d2)^2}{4x}$ $\frac{\pi}{2}(d1 + d2) - 2x + \frac{(d1-d2)}{4x}$ $\frac{\pi}{2}(d1 - d2) + 2x + \frac{(d1-d2)^2}{2x}$ None of the mentioned $\frac{\pi}{2}(d1 + d2)^2 + 2x + \frac{(d1-d2)}{2x}$ $\frac{\pi}{2}(r1 + r2) + 2x + \frac{(r1-r2)^2}{2x}$

          2
Two pulleys of diameters d1 and d2 and at distance x apart are connected by means of an
crossed belt drive. The length of the belt is
(Note that r=d/2)
(1 Point)
$\frac{\pi}{2}(d1 + d2) + 2x + \frac{(d1+d2)^2}{4x}$
$\frac{\pi}{2}(d1 + d2) - 2x + \frac{(d1-d2)}{4x}$
$\frac{\pi}{2}(d1 - d2) + 2x + \frac{(d1-d2)^2}{2x}$
None of the mentioned
$\frac{\pi}{2}(d1 + d2)^2 + 2x + \frac{(d1-d2)}{2x}$
$\frac{\pi}{2}(r1 + r2) + 2x + \frac{(r1-r2)^2}{2x}$

2
Two pulleys of diameters d1 and d2 and at distance x apart are connected by means of an
crossed belt drive. The length of the belt is
(Note that r=d/2)
(1 Point)
(π)/(2)(d1 + d2) + 2x + ((d1+d2)^2)/(4x)
(π)/(2)(d1 + d2) - 2x + ((d1-d2))/(4x)
(π)/(2)(d1 - d2) + 2x + ((d1-d2)^2)/(2x)
None of the mentioned
(π)/(2)(d1 + d2)^2 + 2x + ((d1-d2))/(2x)
(π)/(2)(r1 + r2) + 2x + ((r1-r2)^2)/(2x)

Added by Carolina R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Cyra Jelle Calleja

Step 1

In a crossed belt drive, the belt crosses over itself between the two pulleys. This means that the belt forms an "X" shape between the pulleys. Now, let's break down the length of the belt in the given options: Option 1: d1 + d2 + 2x + d1 + 2√4x This option Show more…

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Two pulleys of diameters d1 and d2 and at a distance x apart are connected by means of a crossed belt drive. The length of the belt is: d1 + d2 + 2x + d1 + 2âˆš4x d1 + d2 - 2x + âˆš(a1 - a2) 4x 2r None of the mentioned d1 + d2 + 2x + d1 - 2âˆš(r1 + r2) + 2x + 1 - 2âˆš2