Question

Two random samples are selected from two independent populations. A summary of the sample sizes, sample means, and sample standard deviations is given below: n1 = 38, x?1 = 50.7, s1 = 6 n2 = 45, x?2 = 76.5, s2 = 13.2 Find a 98% confidence interval for the difference ?1 - ?2 of the means, assuming unequal population variances. -38.04 < ?1 - ?2 < -23.56

          Two random samples are selected from two independent populations. A summary of the sample sizes, sample means, and sample standard deviations is given below:
n1 = 38, x?1 = 50.7, s1 = 6
n2 = 45, x?2 = 76.5, s2 = 13.2
Find a 98% confidence interval for the difference ?1 - ?2 of the means, assuming unequal population variances.
-38.04 < ?1 - ?2 < -23.56

Two random samples are selected from two independent populations. A summary of the sample sizes, sample means, and sample standard deviations is given below:
n1 = 38, x?1 = 50.7, s1 = 6
n2 = 45, x?2 = 76.5, s2 = 13.2
Find a 98% confidence interval for the difference ?1 - ?2 of the means, assuming unequal population variances.
-38.04 < ?1 - ?2 < -23.56

Added by Briana F.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

07/31/2023

Step 1

The point estimate of the difference in means is simply the difference between the sample means: x1 - x2 = 50.7 - 76.5 = -25.8 Show more…

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Two random samples are selected from two independent populations: summary of the sample sizes, sample means; and sample standard deviations given below: n1 = 50, x̄1 = 76.5, s1 = 6 n2 = 51, x̄2 = 50.7, s2 = 3.2 Find a 98% confidence interval for the difference (μ1 - μ2) of the means, assuming unequal population variances. 38.04 23.56