00:01
Hi everyone, in this particular question, two resistance, which is r1 is equal to 10 oom and r2 is equal to 20 oom are connected parallelly, are connected parallelly, where a battery supplies 6 ampere of current to this.
00:27
So, value of current is also given which is equal to 6 ampere.
00:34
We have to find the current in each resistance, current in each resistance.
00:43
So let understand this question by a diagram where these two resistance, one is, one of them is 10 and the second one is 20 and the 6 ampere of current passes through it.
01:03
So it goes i1 here and the i2 here.
01:08
So first of all, we have to find the equivalent resistance so that we find the potential difference in both points.
01:22
For that, then the equivalent resistance, the equivalent resistance, if they are paralleled, then r equivalent is equal to 1 upon r1 plus 1 upon r2 1 upon r1 plus 1 upon r2 then we get 1 upon r equal resistance is equal to 1 upon 10 plus 1 upon 20 if we solve it then we get 3 upon 20 so equivalent resistance if we receive equal those quantities then we get 20 upon 3 20 upon 3 this is the equivalent resistance...