00:01
The given question is two rocks are thrown from the top.
00:05
Now the answer is, it is given that velocity of rock a is equal to 84 .2 meter per second.
00:20
And velocity of rock b is equal to 150 meter per second.
00:27
And height is equal to 700 meter.
00:34
So if we calculate the first a then this plus this minus this is height 700 now if we throw here so velocity of rock a so sign convention upward is positive and downwards is negative so applying motion evaluation, its formula is s is equal to ut plus 1 over 280 square.
01:54
Now s is minus 700 meter, a is minus 9 .9 meter per second square.
02:14
Then it will be 84 .2 meter per second.
02:22
Now, minus 700 is equal to 84 .2t minus 1 over 2 ,000 multiplied by 9 .8 t squared.
02:41
Now, 4 .9 t squared minus 84 .2t, minus 700 is equal to 0.
03:00
Now, t is equal to 23 .117.
03:08
So, minus 6 .128, it is second the value.
03:17
Now time cannot be negative, so the valuation will be t is equal to 23 .3117 second...