00:01
Hello students, in this question we have given two shafts.
00:05
Now for solid shaft we have diameter d1, torque will be t1, twisted angle will be theta 1 and length will be taken as l1.
00:21
For hollow shaft we take diameter, outer will be d2, torque t2, twisted angle will be theta 2 and length is taken as l2.
00:40
Now diameter for inner will be equal to 2 by 3, it is given in question, so this will be 2 by 3 of d2.
00:53
Also as these materials are same so we can write g1 is equal to g2 and length will be equal so l1 will be equal to l2.
01:01
Now for first part to find the ratio of torque we have given that first torque will be equal to torque 2 as the maximum shear stress.
01:14
So this will be written as t1 by j1 into r1 is equal to t2 divided by j2 into r2.
01:26
Now this will be written as t1 divided by pi by 32 into d1 power 4 into d1 divided by 2.
01:41
This will be equal to t2 divided by pi by 32 into outer diameter power 4 minus inner diameter power 4 into d2 divided by 2.
01:58
Now further solving this we can write t1 divided by pi by 32 into d1 power 4 into d1 divided by 2 will be equal to t2 divided by pi by 32 into now putting the equations for here we can write d2 minus 2 by 3 of d2 power 4 multiply of d2 divided by 4...