00:01
For solving this question, remember that electric field always lie away from the positive charge and towards the negative charge.
00:17
Or in the other words, we can say the direction of electric field always away from the positive charge and the direction of electric field is always towards the negative charge.
00:30
And next, due to point charge, we know electric field is given by k.
00:35
K k u over r square means electric field is inversely proportional to the square of the distance means as we go away from the positive charge then the strength of the electric field will reduce and due to negative charge electric field is given by negative k q over r square and from this we can say here electric field is proportional to the negative one over r square in this case, we say that as we go away from the negative charge, the strength of the magnitude of electric field will reduce.
01:16
Now by using this discussion, we solve the given problem.
01:22
Here first we draw the electric field or electric field lines due to positive charge and due to negative charge.
01:29
We know electric field lines always go away from the positive charge and the negative charge.
01:36
And electric field lines always come towards the negative charge.
01:43
Now from this discussion we can say electric field at point b due to this positive charge lies in this direction and electric field 8 .b due to this negative charge lies in this direction.
01:57
Here the direction of both electric fields at point b is same.
02:03
Means here the addition of both electric fields take place.
02:08
And resultant electric field at point b lies in this direction.
02:14
Now at point c, electric field due to this positive charge lies in this direction and electric field due to this negative charge lies in this direction...