00:03
So here for our solution or for our answer, so basically for part a, we have the lowest frequency that leaves minimum signal.
00:14
So that would be n, which is equal to zero.
00:19
We have fmin, one, so 343 hertz.
00:25
For part b, the second lowest frequency is we have n is equal to one, fmin, two.
00:38
We have two times one plus one, we have 343 hertz, which is equal to 1029 hertz, which is equal to 3fmin, one.
00:53
Thus the factor is three.
00:57
For part c, the third lowest frequency, which is our factor is five...