Two springs with spring constants K1 = 1500 N/m and K2 = 3000 N/m are stretched by the same force. The ratio of potential energy stored in spring will be (a) 2 : 1 (b) 1 : 2 (c) 4 : 1 (d) 1 : 4
Added by Anuj C.
Step 1
Given that the same force is applied to both springs, we can use Hooke's law (F = kx) to express the displacement x in terms of the force F and the spring constant k. Show more…
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