00:01
Here, two springs are attached to a block.
00:04
The spring constant of spring 1 is given as k1 equals 9 newton per meter.
00:12
The spring constant of spring 2 is given as 18 newton per meter.
00:19
Now the block has mass 1 kilogram.
00:23
Now, in first case, the springs are attached in parallel combination.
00:30
In parallel combination.
00:34
Here, the effective force constant.
00:37
Effective force constant is equals to kp for parallel combination.
00:44
This is equals to k1 plus k2.
00:48
So kp is equals to 9 plus 18 newton per meter which is equals to 27 newton per meter.
00:58
So this is the effective force constant when the springs are attached in parallel combination.
01:04
Now the block is pulled to a distance of s1 equals 2 cm.
01:10
Now this is equals to 0 .02 meters.
01:15
Therefore the work done by the external force to stretch the spring is given as w equals half k x squared.
01:26
So here in this case we can write it as w1 equals half kp for the parallel combination into s1 square.
01:40
Now this is equals to half into kp is 27 newton per meter into 0 .02 meter square...