00:01
For part a, we'd like to find the speed, wavelength, and frequency of the wave on string x.
00:08
Okay.
00:11
So for string x, our fundamental mode l, or we have l is equal to lambda x over 2.
00:17
So lambda x is equal to 2 times l, or 1 meter.
00:23
But l is equal to 1 half v over frequency.
00:27
So our frequency is v divided by 2l, or 1 over 2l ,000, times.
00:32
The square root of our tension divided by mu.
00:36
So our frequency is 1 over 1 times a square root of 20 times 9 .8 divided by 5 times 10 to the negative 3, which is 198 .1 hertz.
00:49
We'd also like to find the wavelength and frequency.
00:54
Well we have our wavelength.
00:56
We have our frequency.
00:57
Our wavelength is 1 meter.
00:59
Our frequency is 198, and our speed is equal to our square root.
01:08
This is our square root of t divided by mu, which is again, 198 .1 meters per second.
01:18
Now for b, we'd like to find the wavelength of the string on string y...