Question

Two trains are moving at $30 \mathrm{m} / \mathrm{s}$ in opposite directions on the same track. The engineers see simultaneously that they are on a collision course and apply the brakes when they are $1000 \mathrm{m}$ apart. Assuming both trains have the same acceleration, what must this acceleration be if the trains are to stop just short of colliding?

          Two trains are moving at $30 \mathrm{m} / \mathrm{s}$ in opposite directions on the same track. The engineers see simultaneously that they are on a collision course and apply the brakes when they are $1000 \mathrm{m}$ apart. Assuming both trains have the same acceleration, what must this acceleration be if the trains are to stop just short of colliding?

Added by Mireia T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

09/14/2022

Step 1

- Initial velocity of each train, $ v_0 = 30 \, \text{m/s} $. - Distance between the trains, $ d = 1000 \, \text{m} $. - Final velocity of each train, $ v_f = 0 \, \text{m/s} $ (since they must stop just short of colliding). - Acceleration of each Show more…

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Two trains are moving at $30 \mathrm{m} / \mathrm{s}$ in opposite directions on the same track. The engineers see simultaneously that they are on a collision course and apply the brakes when they are $1000 \mathrm{m}$ apart. Assuming both trains have the same acceleration, what must this acceleration be if the trains are to stop just short of colliding?