00:01
In this question, the vector a is having the magnitude of 50 unit and angle is 60 degree.
00:10
So taking the component we will get in x direction 50 cost 60 and in y direction it will be 50 sine 60.
00:20
Now the vector b has magnitude 30 unit and the angle is 30 degree.
00:28
So taking again the magnitude in x direction it will be p.
00:32
Plus 30 cost 30 degree and in y direction it will be 30 sine 60.
00:41
30 sine 30.
00:44
Now if it takes the overall effect, we have to simply add.
00:49
And so we will get in x direction that will be equals to 51i.
01:00
And in y direction, 58 .3.
01:07
3 j.
01:11
So the resultant r will be 51 square plus 58 .3 square so the r will be equals to 77 .45 and the angle will be equal to than theta will be equals to 51 divided by 58 sorry 58 d .3 divided by 51 so after doing the calculation we will get theta equals to 48 .67 degree now let's represent this we can say that if this is vector a let's displace the vector b with somewhere here keeping the magnitude and direction same but changing its initial position.
02:26
Now this is, let's say the vector c which is the resultant of the vector a and vector b...